8x^2+3x+3=4

Solution for 8x^2+3x+3=4 equation:

8x^2+3x+3=4

We move all terms to the left:

8x^2+3x+3-(4)=0

We add all the numbers together, and all the variables

8x^2+3x-1=0

a = 8; b = 3; c = -1;
Δ = b2-4ac
Δ = 32-4·8·(-1)
Δ = 41
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{41}}{2*8}=\frac{-3-\sqrt{41}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{41}}{2*8}=\frac{-3+\sqrt{41}}{16}
$